A simple Swift Playground showcasing the Monty Hall problem. For more info on the problem check here.


At first the statement might not make sense, however the first time you choose a door your probabilities are 1/3 that you’ve got it correct, so the two other doors would represent a 2/3 chance of winning and since one door is not “choosable” (because it has been opened) you end up with a 2/3 chance of winning in a single door.

If you run the simulation on Swift Playground that is exactly what you will get.


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