wordlepermutations
For tryharding Wordle without cheating  Swift PlaygroundBook
I used to bruteforce all possible combinations by hand when both enough green/yellow letters are uncovered and I still have no idea what’s going on. Then I decided to write some code to automate this process.
Usage
Important: Swift Playgrounds is required to run this PlaygroundBook
Initial Setup
Create an instance of Permuter
with its only initializer (no arguments)
Adding Letters

Use
.addGreen(letter:at:)
to add a letter marked green 
Use
.addYellow(letter:at:)
to add a letter marked yellow
Important: the
at:
parameter is indexed from 0, not 1
Note: errors will be thrown when the letters you add conflict with each other logically
Run Permutations
.permute()
returns the result String
Sample Output
Setup code:
// overall: ðŸŸ¨â¬›ðŸŸ©ðŸŸ¨â¬›
// I: â¬›â¬›ðŸŸ¨ðŸŸ¨â¬›
// T: ðŸŸ¨â¬›â¬›â¬›â¬›
// R: â¬›â¬›ðŸŸ©â¬›â¬›
let permuter = Permuter()
permuter.addYellow(letter: "I", at: 2)
permuter.addYellow(letter: "I", at: 3)
permuter.addYellow(letter: "T", at: 0)
permuter.addGreen(letter: "R", at: 2)
print(permuter.permute())
Output:
_ _ R T I
_ T R _ I
_ T R T I
_ I R _ T
_ I R T _
_ I R T T
_ I R T I
I _ R _ T
I _ R T _
I _ R T T
I _ R T I
I T R _ _
I T R _ T
I T R _ I
I T R T _
I T R T T
I T R T I
I I R _ T
I I R T _
I I R T T
I I R T I
Future development
New features may or may not be added in the future.